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11a^2-44=0
a = 11; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·11·(-44)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*11}=\frac{-44}{22} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*11}=\frac{44}{22} =2 $
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